The Complete Codes

Difference Between Procedure Oriented Programming (POP) & Object-Oriented Programming (OOP) | C++ Programming Procedure Oriented Programming Object-Oriented Programming Divided Into In POP, the program is divided into small parts called  functions . In OOP, the program is divided into parts called  objects . Importance In POP, Importance is not given to  data  but to functions as well as the  sequence  of actions to be done. In OOP, Importance is given to the data rather than procedures or functions because it works as a  real world . Approach POP follows  Top-Down approach . OOP follows  Bottom-Up approach . Access Specifiers POP does not have any access specifier. OOP has access specifiers named Public, Private, Protected, etc. Data Moving In POP, Data can move freely from function to function in the system. In OOP, objects can move and communicate with each other through member functions. Expansion To add new data and function in POP is not so easy. OOP provides an

C++ Program For Banking System Using Class #include <iostream> using namespace std ; #include <iomanip> class bank {     char name [ 20 ];     int acno ;     char actype [ 20 ];     int bal ; public:     void opbal ( void );     void deposit ( void );     void withdraw ( void );     void display ( void ); }; void bank :: opbal ( void ) {     cout << endl          << endl;     cout << "Enter Name :-" ;     cin >> name ;     cout << "Enter A/c no. :-" ;     cin >> acno ;     cout << "Enter A/c Type :-" ;     cin >> actype ;     cout << "Enter Opening Balance:-" ;     cin >> bal ; } void bank :: deposit ( void ) {     cout << "Enter Deposit amount :-" ;     int deposit = 0 ;     cin >> deposit ;     cout << " \n Deposit Balance = " << bal + deposit ; } void bank :: withdraw ( void ) {     int withdraw ;     c

Constructor Overloading When more than one constructor function is defined in a class, then it is called constructor overloading or the use of multiple  constructors  in a class. It is used to increase the flexibility of a class by having a greater number of constructors for a single class. Overloading constructors in C++ programming gives us more than one way to initialize objects in a class.

C++ Program To Find Negation Of A Number #include <iostream> using namespace std ; class point {     int x , y ; public:     void getdata ()     {         cout << "Enter x and y coordinate:" ;         cin >> x >> y ;     }     void display ()     {         cout << "(" << x << "," << y << ")" ;     }     point operator- ()     {         point t ;         t . x = - x ;         t . y = - y ;         return t ;     } }; int main () {     point p , q ;     p . getdata ();     q = - p ;     cout << "q=" ;     q . display (); } OUTPUT Enter x and y coordinate: 5 4 q=(-5,-4)

Access Modifiers in C++ Access modifiers are constructs that define the scope and visibility of members of a class. There are three access modifiers:

Types of Inheritance A class can inherit properties from one or more classes and from one or more levels. On the basis of this concept, there are five types of inheritance. Single Inheritance Multiple Inheritance Hierarchical Inheritance Multilevel Inheritance Hybrid Inheritance Single Inheritance In single inheritance, a class is derived from only one base class. The example and figure below show this inheritance. Example class A {  members of A }; class B  :  public A {  members of B }; Multiple Inheritance In this inheritance, a class is derived from more than one base class. The example and figure below show this inheritance. Implementation Skeleton: class A { members of A }; class B {  members of B }; class C  : public A, public B  { members of C }; Hierarchical Inheritance In this type, two or more classes inherit the properties of one base class. The example and figure below show this inheritance. Implementation Skeleton: class A { member

C++ Program To Find Factorial Of Two Numbers Using Recursion Function #include<iostream> using namespace std; long int fact(int); int main() { int n1,n2; cout<<"Enter number"< cin>>n1>>n2; cout<<n1<<"! = "<<fact(n1)<<endl; cout<<n2<<"! = "<<fact(n2)<<endl; } long int fact(int n) { if(n<=1) return 1; else   return (n*fact(n-1)); } OUTPUT Enter number 5 4 5! = 120 4! = 24