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C Program To Check The String Is Valid Identifier Or Not #include <stdio.h> #include <conio.h> #include <string.h> int main () { char string [ 25 ]; int count= 0 ,flag; printf ( "Enter any string: " ); gets (string); if ( ( string [ 0 ]>= 'a' && string [ 0 ]<= 'z' )||( string [ 0 ]>= 'A' && string [ 0 ]<= 'Z' )||( string [ 0 ]== '_' )) {     for ( int i= 1 ;i<= strlen (string);i++)     {         if (( string [i]>= 'a' && string [i]<= 'z' )||( string [i]>= 'A' && string [i]<= 'Z' )||( string [i]>= '0' && string [i]<= '9' )||( string [i]== '-' ))     {     count++;     }        }     if (count== strlen (string))     {       flag= 0 ;     } } else {     flag= 1 ; } if (flag== 1 )     printf ( " %s is not valid identifier" ,string); else     printf ( " %s is valid ident

C Program To Accept The String Starting With 01 And Ending With 011 #include <stdio.h> #include <string.h> int main () {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "enter the string which only contain 0 and 1 \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == '0' && q == 0 )             q = 1 ;         else if ( str [i] == '1' && q == 0 )             q = 6 ;         else if ( str [i] == '0' && q == 1 )             q = 6 ;         else if ( str [i] == '1' && q == 1 )             q = 2 ;         else if ( str [i] == '0' && q == 2 )             q = 3 ;         else if ( str [i] == '1' && q == 2 )             q = 2 ;         else if ( str [i] == '0' && q == 3 )             q = 3 ;         else if ( str [i] == '1' &&a

C Program To Accept The String Starting With ab And Ending With abb  #include <stdio.h> #include <string.h> int main ( int argc , char const * argv []) {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "enter the string which only contain a and b \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == 'a' && q == 0 )             q = 1 ;         else if ( str [i] == 'b' && q == 0 )             q = 6 ;         else if ( str [i] == 'a' && q == 1 )             q = 6 ;         else if ( str [i] == 'b' && q == 1 )             q = 2 ;         else if ( str [i] == 'a' && q == 2 )             q = 3 ;         else if ( str [i] == 'b' && q == 2 )             q = 2 ;         else if ( str [i] == 'a' && q == 3 )             q = 3 ;         else i

C Program To Accept The String That Ends With 01 #include <stdio.h> #include <math.h> #include <string.h> int main () {     char s [ 100 ];     int i = 0 , q = 0 , l;     printf ( "Enter stringover {0,1}: \n " );         scanf ( " %s " ,s);     l = strlen (s);     for (i = 0 ; s [i] != ' \0 ' ; i++)     {         if ( s [i] == '0' && q == 0 )         {             if (i == (l - 2 ))                 q = 1 ;             else                 q = 0 ;         }         else if ( s [i] == '1' && q == 0 )             q = 0 ;         else if ( s [i] == '1' && q == 1 )             q = 2 ;     }     if (q == 2 )     {         printf ( "Accepted. \n\n " );     }     else         printf ( "Rejected." );     return 0 ; } OUTPUT #1 OUTPUT #2 Related Posts C Program To Accept The String Having Even Length | C Programming C Program To Accept The String T

C Program To Accept The String Starting With 01 #include <stdio.h> #include <string.h> int main () {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "enter the string which only contain 0 and 1 \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == '0' && q == 0 )             q = 1 ;         else if ( str [i] == '1' && q == 0 )             break ;         else if ( str [i] == '1' && q == 1 )             q = 2 ;         else if ( str [i] == '0' && q == 1 )             break ;         else if ( str [i] == '0' && q == 2 )             q = 2 ;         else if ( str [i] == '1' && q == 2 )             q = 2 ;     }     if (q == 2 )         printf ( "Given string is accepted \n " );     else         printf ( "Given string is not accepted \n "

C Program To Accept The String Having Length At Least Two #include <stdio.h> #include <string.h> int main () {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "Enter the string which only contain a and b \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == 'a' && q == 0 )             q = 1 ;         else if ( str [i] == 'b' && q == 0 )             q = 1 ;         else if ( str [i] == 'a' && q == 1 )             q = 2 ;         else if ( str [i] == 'b' && q == 1 )             q = 2 ;         else if ( str [i] == 'a' && q == 2 )             q = 3 ;         else if ( str [i] == 'b' && q == 2 )             q = 3 ;         else if ( str [i] == 'a' && q == 3 )             q = 3 ;         else if ( str [i] == 'b' && q == 3

C Program To Accept The String Having Even Length #include <stdio.h> #include <string.h> int main () {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "Enter the string which only contain 0 and 1 \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == '0' && q == 0 )             q = 2 ;         else if ( str [i] == '1' && q == 0 )             q = 1 ;         else if ( str [i] == '0' && q == 1 )             q = 3 ;         else if ( str [i] == '1' && q == 1 )             q = 0 ;         else if ( str [i] == '0' && q == 2 )             q = 0 ;         else if ( str [i] == '1' && q == 2 )             q = 3 ;         else if ( str [i] == '0' && q == 3 )             q = 1 ;         else if ( str [i] == '1' && q == 3 )      

C Program To Accept The String That Ends With 011 #include <stdio.h> #include <string.h> int main () {     char str [ 10 ];     int len, i, q = 0 ;     printf ( "Enter the string which only contain 0 and 1 \n " );     scanf ( " %s " , str);     len = strlen (str);     for (i = 0 ; i <= len; i++)     {         if ( str [i] == '0' && q == 0 )             q = 1 ;         else if ( str [i] == '1' && q == 0 )             q = 0 ;         else if ( str [i] == '1' && q == 1 )             q = 2 ;         else if ( str [i] == '0' && q == 1 )             q = 1 ;         else if ( str [i] == '0' && q == 2 )             q = 1 ;         else if ( str [i] == '1' && q == 2 )             q = 3 ;         else if ( str [i] == '1' && q == 3 )             q = 0 ;         else if ( str [i] == '0' && q == 3 )