C Program To Accept The String Starting With 01 And Ending With 011 | C Programming

C Program To Accept The String Starting With 01 And Ending With 011

#include <stdio.h>
#include <string.h>
int main()
{
    char str[10];
    int len, i, q = 0;
    printf("enter the string which only contain 0 and 1\n");
    scanf("%s", str);
    len = strlen(str);
    for (i = 0; i <= len; i++)
    {
        if (str[i] == '0' && q == 0)
            q = 1;
        else if (str[i] == '1' && q == 0)
            q = 6;
        else if (str[i] == '0' && q == 1)
            q = 6;
        else if (str[i] == '1' && q == 1)
            q = 2;
        else if (str[i] == '0' && q == 2)
            q = 3;
        else if (str[i] == '1' && q == 2)
            q = 2;
        else if (str[i] == '0' && q == 3)
            q = 3;
        else if (str[i] == '1' && q == 3)
            q = 4;
        else if (str[i] == '0' && q == 4)
            q = 3;
        else if (str[i] == '1' && q == 4)
            q = 5;
        else if (str[i] == '0' && q == 5)
            q = 3;
        else if (str[i] == '1' && q == 5)
            q = 2;
        else if (str[i] == '0' && q == 6)
            q = 6;
        else if (str[i] == '1' && q == 6)
            q = 6;
    }
    if (q == 5)
        printf("Given string is accepted\n");
    else
        printf("Given string is not accepted\n");
}

Output #1

Output #2

Output #3

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