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Top 10 Programming Language to learn in 2023

Are you a programming enthusiast looking to stay ahead of the curve in 2023? With the ever-evolving tech landscape, keeping up with the Best Programming Language to learn can be a daunting task. Fear not, as we have compiled a list of the top 10 Programming Languages that you should consider learning in 2023. Python: This versatile language continues to dominate in 2023, with its ease of use, readability, and a vast library of modules. JavaScript: As web development grows increasingly popular, JavaScript remains a crucial player, with its ability to create dynamic and interactive web pages. Java: This language has stood the test of time and remains a popular choice for enterprise software development. C++: A staple in the gaming and systems development industries, C++ offers exceptional performance and memory management. Swift: Apple's preferred language for iOS app development, Swift continues to grow in popularity with its simplicity and reliability. R: As data science and machin...

Implementation Of Mono Alphabetic Cipher Encryption-Decryption

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Mono Alphabetic Cipher Encryption-Decryption Introduction It is Better than Caesar Cipher. If, instead the “cipher” line can be any permutation of the key 26 alphabetic characters, then there are 26! Or greater than 4 * 10 26  possible keys. This is 10 orders of magnitude greater than the key space for DES and would seem to as a Mono-alphabetic substitution cipher, because a single cipher alphabet is used per message. There is however, another line of attack. If one analytically knows the nature of the plain text, then the analyst can exploit the regularities of the language. Limitations Monoalphabetic ciphers are easy to break because they reflect the frequency data of the original alphabet. A countermeasure is to provide multiple substitutes, known as homophones, for a single letter C Progrm to Encryp the imputed text using Mono Alphabetic Cipher. #include <stdio.h> #include <string.h> int main () {     char pt [ 52 ] = { 'A' , 'B' , 'C' , ...

Recurrences And Their Solution Methods Continue

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Recurrences And Their Solution Methods Recursion Tree Just Simplification of Iteration method: Consider The Recurrences Second Example Example Three Master Method Cookbook solution for some recurrences of the form T(n) = a . T(n/b) + f(n) where a>=1, b>1, f(n) asymptotically positive Describe its cases 

Recurrences And Their Solution Methods

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Recurrences Recursive algorithms are described by using recurrence relations. A recurrence is an inequality that describes a problem in terms of itself. For Example: Recursive algorithm for finding factorial   T(n)=1     when n =1 T(n)=T(n-1) + O(1)    when  n>1 Recursive algorithm for finding Nth Fibonacci number T(1)=1     when n=1 T(2)=1     when n=2 T(n)=T(n-1) + T(n-2) +O(1)     when n>2 Recursive algorithm for binary search T(1)=1     when n=1 T(n)=T(n/2) + O(1)    when n>1 Techniques for Solving Recurrences We’ll use four techniques: Iteration method Recursion Tree Substitution Master Method   – for divide & conquer Characteristic Equation   – for linear Iteration method Expand the relation so that summation independent on n is obtained. Bound the summation e.g.    T(n)= 2T(n/2) +1  when n>1 T(n)= 1  ...

C Program To Check The String Is Valid Identifier Or Not | C Programming

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C Program To Check The String Is Valid Identifier Or Not #include <stdio.h> #include <conio.h> #include <string.h> int main () { char string [ 25 ]; int count= 0 ,flag; printf ( "Enter any string: " ); gets (string); if ( ( string [ 0 ]>= 'a' && string [ 0 ]<= 'z' )||( string [ 0 ]>= 'A' && string [ 0 ]<= 'Z' )||( string [ 0 ]== '_' )) {     for ( int i= 1 ;i<= strlen (string);i++)     {         if (( string [i]>= 'a' && string [i]<= 'z' )||( string [i]>= 'A' && string [i]<= 'Z' )||( string [i]>= '0' && string [i]<= '9' )||( string [i]== '-' ))     {     count++;     }        }     if (count== strlen (string))     {       flag= 0 ;     } } else {     flag= 1 ; } if (flag== 1 )     printf ( " %s is not valid identifier" ,string); else ...

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