C Program To Accept The String Starting With 01 And Ending With 011 | C Programming
C Program To Accept The String Starting With 01 And Ending With 011 #include <stdio.h> #include <string.h> int main () { char str [ 10 ]; int len, i, q = 0 ; printf ( "enter the string which only contain 0 and 1 \n " ); scanf ( " %s " , str); len = strlen (str); for (i = 0 ; i <= len; i++) { if ( str [i] == '0' && q == 0 ) q = 1 ; else if ( str [i] == '1' && q == 0 ) q = 6 ; else if ( str [i] == '0' && q == 1 ) q = 6 ; else if ( str [i] == '1' && q == 1 ) q = 2 ; else if ( str [i] == '0' && q == 2 ) q = 3 ; else if ( str [i] == '1' && q == 2 ) q = 2 ; else if ( str [i] == '0' && q == 3 ) q = 3 ; else if ( str [i] == '1' &&a