The Complete Codes

C program to find the Cartesian Product of two sets   Cartesian product  is a mathematical operation that returns a set (or  product set  or simply  product ) from multiple sets. That is, for sets  A  and  B , the Cartesian product  A  ×  B  is the set of all ordered pairs  ( a ,  b )  where  a  ∈  A  and  b  ∈  B . Products can be specified using set-builder notation, e.g. {\displaystyle A\times B=\{\,(a,b)\mid a\in A\ {\mbox{ and }}\ b\in B\,\}.}

This Program helps to calculate intersection of two sets, union of two sets, differences of two sets and symmetric difference of two sets using one simple program in which different variables are declared so that it can be useful to find intersection of two sets, union of two sets, differences of two sets and symmetric difference of two sets Codes #include <stdio.h> int a [ 10 ], b [ 10 ], c [ 10 ], d [ 10 ], i , j , k = 0 , n , m , flag = 0 ; void unio () {     for ( i = 0 ; i < n ; i ++)     {         c [ k ] = a [ i ];         k ++;     }     for ( i = 0 ; i < m ; i ++)     {         flag = 0 ;         for ( j = 0 ; j < n ; j ++)         {             if ( b [ i ] == a [ j ])             {                 flag = 1 ;                 break ;             }         }         if ( flag == 0 )         {             c [ k ] = b [ i ];             k ++;         }     }     printf ( " \n Union \n " );     for ( i = 0 ; i < k ; i ++)

C Program To Calculate Age and Compare Using Concept of Fuzzy Set  #include <stdio.h> int i , age [ 5 ]; float a [ 5 ], b [ 5 ], c [ 5 ]; char name [ 5 ][ 15 ]; void unio () {     for ( i = 0 ; i < 5 ; i ++)     {         if ( a [ i ] >= b [ i ])             c [ i ] = a [ i ];         else             c [ i ] = b [ i ];     }     printf ( "union \n " );     printf ( "{ " );     for ( i = 0 ; i < 5 ; i ++)     {         printf ( " %.2f / %s ," , c [ i ], name [ i ]);     }     printf ( "}" ); } void intersection () {     for ( i = 0 ; i < 5 ; i ++)     {         if ( a [ i ] <= b [ i ])             c [ i ] = a [ i ];         else             c [ i ] = b [ i ];     }     printf ( " \n intersection \n " );     printf ( "{" );     for ( i = 0 ; i < 5 ; i ++)     {         printf ( " %.2f / %s , " , c [ i ], name [ i ]);     }     printf ( "}" ); } void comple