C Program For Prim's Algorithm To Find Shortest Path | C Programming

C Program For Prim's Algorithm To Find Shortest Path

#include <stdio.h>
#include <stdlib.h>
#define infinity 9999
#define MAX 20
int G[MAX][MAX], spanning[MAX][MAX], n;
int prims();
int main()
{
    int i, j, total_cost;
    printf("Enter no. of vertices:");
    scanf("%d", &n);
    printf("\nEnter the adjacency matrix:\n");
    for (i = 0; i < n; i++)
        for (j = 0; j < n; j++)
            scanf("%d", &G[i][j]);
    total_cost = prims();
    printf("\nspanning tree matrix:\n");
    for (i = 0; i < n; i++)
    {
        printf("\n");
        for (j = 0; j < n; j++)
            printf("%d\t", spanning[i][j]);
    }
    printf("\n\nTotal cost of spanning tree=%d", total_cost);
    return 0;
}
int prims()
{
    int cost[MAX][MAX];
    int u, v, min_distance, distance[MAX], from[MAX];
    int visited[MAX], no_of_edges, i, min_cost, j;
    for (i = 0; i < n; i++)
        for (j = 0; j < n; j++)
        {
            if (G[i][j] == 0)
                cost[i][j] = infinity;
            else
                cost[i][j] = G[i][j];
            spanning[i][j] = 0;
        }
    distance[0] = 0;
    visited[0] = 1;
    for (i = 1; i < n; i++)
    {
        distance[i] = cost[0][i];
        from[i] = 0;
        visited[i] = 0;
    }
    min_cost = 0;
    no_of_edges = n - 1;
    while (no_of_edges > 0)
    {
        min_distance = infinity;
        for (i = 1; i < n; i++)
            if (visited[i] == 0 && distance[i] < min_distance)
            {
                v = i;
                min_distance = distance[i];
            }
        u = from[v];
        spanning[u][v] = distance[v];
        spanning[v][u] = distance[v];
        no_of_edges--;
        visited[v] = 1;
        for (i = 1; i < n; i++)
            if (visited[i] == 0 && cost[i][v] < distance[i])
            {
                distance[i] = cost[i][v];
                from[i] = v;
            }
        min_cost = min_cost + cost[u][v];
    }
    return (min_cost);
}

Output